大老的打狗教程第一篇如解掉hasp的狗
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大老的打狗教程第一篇如解掉hasp的狗!希望对大家有所帮助!大老=[DCG]=
程序名:国外的工程类软件dasxx
作者：大老
保护 :hasp4 m1这是以色列的狗 m1是代表他有储存器
所用工具:trw2000 wasm32
我写的打狗教程这是第一篇!我共会写3篇的!写第一篇写个网上中文的教程比较少的hasp4的狗保护的软件!
我只是大体说一下破解的思路!
希望对大家有所帮助!
(1) 第一部分
=============================================================
:0042659A 50 push eax
:0042659B 51 push ecx
:0042659C 52 push edx
:0042659D 53 push ebx
:0042659E 68FE3F0000 push 00003FFE ===>这就是hasp狗读狗时要用到的密码! (1)
:004265A3 687B1D0000 push 00001D7B ===>hasp狗的密码! (2)
:004265A8 6800000000 push 00000000
:004265AD 6800000000 push 00000000
:004265B2 6801000000 push 00000001
:004265B7 E8A7FBFFFF call 00426163 ====>读狗 (1)
:004265BC 83C424 add esp, 00000024
:004265BF 8B45FC mov eax, dword ptr [ebp-04]==> 读狗后返回值=1就是有狗!
:004265C2 B901000000 mov ecx, 00000001
:004265C7 39C8 cmp eax, ecx
:004265C9 0F85EF020000 jne 004268BE ===> 跳就完蛋
:004265CF 8D45F0 lea eax, dword ptr [ebp-10]
:004265D2 8D4DF4 lea ecx, dword ptr [ebp-0C]
:004265D5 8D55F8 lea edx, dword ptr [ebp-08]
:004265D8 8D5DFC lea ebx, dword ptr [ebp-04]
:004265DB 50 push eax
:004265DC 51 push ecx
:004265DD 52 push edx
:004265DE 53 push ebx
:004265DF 68FE3F0000 push 00003FFE
:004265E4 687B1D0000 push 00001D7B
:004265E9 6800000000 push 00000000
:004265EE 6800000000 push 00000000
:004265F3 6805000000 push 00000005
:004265F8 E866FBFFFF call 00426163 ========>读狗(2)
:004265FD 83C424 add esp, 00000024
:00426600 8B45FC mov eax, dword ptr [ebp-04] ==> 读狗后返回值=1就是有狗!
:00426603 B901000000 mov ecx, 00000001
:00426608 39C8 cmp eax, ecx
:0042660A 0F85C2010000 jne 004267D2 ===> 跳就完蛋
:00426610 8B45F8 mov eax, dword ptr [ebp-08] ===>另外一个返回值
:00426613 39C8 cmp eax, ecx
:00426615 0F85B7010000 jne 004267D2 ====>跳就完蛋!
:0042661B 8D0518E74500 lea eax, dword ptr [0045E718]
:00426621 8B4DF4 mov ecx, dword ptr [ebp-0C]
:00426624 668908 mov word ptr [eax], cx
:00426627 6885510000 push 00005185
:0042662C 8D05BC614200 lea eax, dword ptr [004261BC]
:00426632 8D4DE0 lea ecx, dword ptr [ebp-20]
:00426635 51 push ecx
:00426636 FFD0 call eax 计算返回的数据
:00426638 83C408 add esp, 00000008
:0042663B 8B45E0 mov eax, dword ptr [ebp-20]====>返回数据(1) 正确值是bb2
:0042663E B9B20B0000 mov ecx, 00000BB2 这里是要比较的值!
:00426643 39C8 cmp eax, ecx ===>比较
:00426645 0F8530000000 jne 0042667B ===>跳到报错
:0042664B 8B45E4 mov eax, dword ptr [ebp-1C] ====>返回数据(2) 正确值是A6FE
:0042664E B9FEA60000 mov ecx, 0000A6FE
:00426653 39C8 cmp eax, ecx ===>比较
:00426655 0F8520000000 jne 0042667B ===>跳到报错
:0042665B 8B45E8 mov eax, dword ptr [ebp-18] ====>返回数据(3) 正确值是6A14
:0042665E B9146A0000 mov ecx, 00006A14
:00426663 39C8 cmp eax, ecx ===>比较
:0426665 0F8510000000 jne 0042667B ===>跳到报错 !
:0042666B 8B45EC mov eax, dword ptr [ebp-14]====>返回数据(4) 正确值是714D
:0042666E B94D710000 mov ecx, 0000714D
:00426673 39C8 cmp eax, ecx ===>比较 相等的话跳到正确处理流程
:00426675 0F84FC000000 je 00426777 ===>跳到正确处理流程 ===关键(1)====
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:00426645(C), :00426655(C), :00426665(C)
|
:0042667B 8D0552924700 lea eax, dword ptr [00479252]
:00426681 6801000000 push 00000001
:00426686 50 push eax
:00426687 6800000000 push 00000000
:00426687 6800000000 push 00000000
* Reference To: cvirt.LoadPanel, Ord:0133h
|
:0042668C E891B3FDFF Call 00401A22
:00426691 8D4DDC lea ecx, dword ptr [ebp-24]
:00426694 8901 mov dword ptr [ecx], eax
:00426696 8B45DC mov eax, dword ptr [ebp-24]
:00426699 B900000000 mov ecx, 00000000
:0042669E 39C8 cmp eax, ecx
:004266A0 0F8D20000000 jnl 004266C6
* Reference To: cvirt.CVI_Beep, Ord:0259h
|
:004266A6 E845B8FDFF Call 00401EF0
:004266AB 8D05EA924700 lea eax, dword ptr [004792EA]
:004266B1 8D0DAA924700 lea ecx, dword ptr [004792AA]
:004266B7 50 push eax
:004266B8 51 push ecx
* Reference To: cvirt.MessagePopup, Ord:014Dh ===>报错信息!
|
:004266B9 E8CCB7FDFF Call 00401E8A
:004266BE 8D056A674200 lea eax, dword ptr [0042676A]
:004266C4 FFE0 jmp eax
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004266A0(C)
|
:004266C6 6800000000 push 00000000
:004266CB 6812020000 push 00000212
:004266D0 6803000000 push 00000003
===========================================================
你这样处理后运行程序还会有问题的!看样子是没有解决完!咱们在来看看!
第二部分
===================================================================================================
第一部分的程序(===关键(1)====)跳转后就到了这里le's go
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00426675(C)
|
:00426777 E8CBFBFFFF call 00426347
:0042677C 8D45FC lea eax, dword ptr [ebp-04]
:0042677F B903000000 mov ecx, 00000003
:00426784 8908 mov dword ptr [eax], ecx
:00426786 8D4DF0 lea ecx, dword ptr [ebp-10]
:00426789 8D55F4 lea edx, dword ptr [ebp-0C]
:0042678C 8D5DF8 lea ebx, dword ptr [ebp-08]
:0042678F 51 push ecx
:00426790 52 push edx
:00426791 53 push ebx
:00426792 50 push eax
:00426793 68FE3F0000 push 00003FFE
:00426798 687B1D0000 push 00001D7B
:0042679D 6800000000 push 00000000
:004267A2 6800000000 push 00000000
:004267A7 6803000000 push 00000003
:004267AC E8B2F9FFFF call 00426163 ====>这里又有一处读狗!
:004267B1 83C424 add esp, 00000024
:004267B4 8B45F4 mov eax, dword ptr [ebp-0C] ====>返回值(1)应该是0
:004267B7 B900000000 mov ecx, 00000000
:004267BC 39C8 cmp eax, ecx ===>比较
:004267BE 0F85DE010000 jne 004269A2 不跳
:004267C4 8B45F8 mov eax, dword ptr [ebp-08]
:004267C7 0FB7C0 movzx eax, ax
:004267CA 8D0DA7694200 lea ecx, dword ptr [004269A7] 注意这里ecx的值是从这里的地址里来的
:004267D0 FFE1 jmp ecx =======>跳到下一个部分!go ====关键2===
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0042660A(C), :00426615(C)
|
:004267D2 8D0545924700 lea eax, dword ptr [00479245]
:004267D8 6801000000 push 00000001
:004267DD 50 push eax
:004267DE 6800000000 push 00000000
* Reference To: cvirt.LoadPanel, Ord:0133h
|
:004267E3 E83AB2FDFF Call 00401A22
:004267E8 8D4DDC lea ecx, dword ptr [ebp-24]
:004267EB 8901 mov dword ptr [ecx], eax
:004267ED 8B45DC mov eax, dword ptr [ebp-24]
:004267F0 B900000000 mov ecx, 00000000
:004267F5 39C8 cmp eax, ecx
:004267F7 0F8D20000000 jnl 0042681D
* Reference To: cvirt.CVI_Beep, Ord:0259h
|
:004267FD E8EEB6FDFF Call 00401EF0
:00426802 8D05BE924700 lea eax, dword ptr [004792BE]
:00426808 8D0D96924700 lea ecx, dword ptr [00479296]
:0042680E 50 push eax
:0042680F 51 push ecx
* Reference To: cvirt.MessagePopup, Ord:014Dh ====>出错信息!
|
:00426810 E875B6FDFF Call 00401E8A
:00426815 8D05A9684200 lea eax, dword ptr [004268A9]
:0042681B FFE0 jmp eax
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004267F7(C)
|
:0042681D 6800000000 push 00000000
:00426822 6812020000 push 00000212
:00426827 6803000000 push 00000003
:0042682C 8B45DC mov eax, dword ptr [ebp-24]
:0042682F 50 push eax
* Reference To: cvirt.SetCtrlAttribute, Ord:00AEh
|
:00426830 E8BFACFDFF Call 004014F4
:00426835 83C410 add esp, 00000010
:00426838 6800000000 push 00000000
:0042683D 6812020000 push 00000212
:00426842 6804000000 push 00000004
=============================================================
经过上部分!咱们看看下面部分如何! 经过对====关键2===的跟踪发现!到了下面的程序!
:0042AFCE 8908 mov dword ptr [eax], ecx
:0042AFD0 E8B1B5FFFF call 00426586
:0042AFD5 8D8DE8FEFFFF lea ecx, dword ptr [ebp+FFFFFEE8]
:0042AFDB 668901 mov word ptr [ecx], ax
:0042AFDE 668B85E8FEFFFF mov ax, word ptr [ebp+FFFFFEE8]
:0042AFE5 0FB7C0 movzx eax, ax
:0042AFE8 B901000000 mov ecx, 00000001
:0042AFED 39C8 cmp eax, ecx ======注意这个比较
:0042AFEF 0F8432000000 je 0042B027 =====>不跳就over
* Possible Reference to String Resource ID=65535: "Das32"
|
:0042AFF5 B9FFFF0000 mov ecx, 0000FFFF
:0042AFFA 39C8 cmp eax, ecx
:0042AFFC 0F8425000000 je 0042B027
* Reference To: cvirt.CVI_Beep, Ord:0259h
|
:0042B002 E8E96EFDFF Call 00401EF0
:0042B007 8D0504B04700 lea eax, dword ptr [0047B004]
:0042B00D 8D0DAFB34700 lea ecx, dword ptr [0047B3AF]
:0042B013 50 push eax
:0042B014 51 push ecx
* Reference To: cvirt.MessagePopup, Ord:014Dh =====出错信息!
|
:0042B015 E8706EFDFF Call 00401E8A
:0042B01A 6800000000 push 00000000
:0042B01F E82F75FDFF call 00402553
:0042B024 83C404 add esp, 00000004
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:0042AFEF(C), :0042AFFC(C)
|
:0042B027 8D45FC lea eax, dword ptr [ebp-04] ====正确的流程!
:0042B02A 50 push eax
:0042B02B 6801000000 push 00000001
=============================================================
经过了这部分后狗部分就解掉了!
总结!
上面的部分只是解狗里面的一种而已!想这个软件还有好几种解法!这种解法比较容易理解!呵呵~我就献丑了!希望大家不要笑我!
希望大家经常来我的论坛来看看交流一下!现在有些人对我有意见!哪是不可避免的!也是很正常的!!谢谢大家看完此文! 如果你觉得写的还行请回个贴子!支持一下!谢谢!
如果要转载请保留完整
大老=[DCG]=
dalao@top86.com
http://dalao2002.yeah.net
2002.6.25
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