*出租销售系统 5.6--算法分析
-
下载地址 
http://www.zzshow.com/bookVcd.exe
加密方式：注册码+ 反跟踪 +反汇编
功能限制：功能限制
PJ工具：W32Dasm8.93黄金版，FI2.5，OLLYDBG1.09中文修正版
PJ日期：2003-04-20
作者newlaos申明：只是学习，请不用于商业用途或是将本文方法制作的注册机任意传播，造成后果，本人一概不负。
1、先用FI2.5看一下主文件“bookVcd.exe”，没有加壳，程序是用DELPHI编写的
2、用W32Dasm8.93黄金版对bookVcd.exe进行静态反汇编，再用串式数据参考，找到"注册码错误，请与作者联系"，双击来到下面代码段。
3、该软件对TRW20001.23进行反调试，也就是说不能用TRW调试，一调试就出错。只是能用OLLYDBG1.09进行动态调试，下断BPX 00575C56(通常在注册成功与否的前面一些下断，这样，才能找到关键部分)，
输入假码: 78787878
.......
.......
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00575BE6(C)
|
:00575C56 6A00 push 00000000 <===你会发现在这里设才能断下来。作者为了防破解在上面的代码段动了些手脚，如果不知道，就很容易进行死胡同。
:00575C58 49 dec ecx
:00575C59 75F9 jne 00575C54
:00575C5B 53 push ebx
:00575C5C 8BD8 mov ebx, eax
:00575C5E 33C0 xor eax, eax
:00575C60 55 push ebp
:00575C61 68B35D5700 push 00575DB3
:00575C66 64FF30 push dword ptr fs:[eax]
:00575C69 648920 mov dword ptr fs:[eax], esp
:00575C6C 8D55F8 lea edx, dword ptr [ebp-08]
:00575C6F 8B8300030000 mov eax, dword ptr [ebx+00000300]
:00575C75 E8363DEDFF call 004499B0 <===算出注册码的长度
:00575C7A 8B45F8 mov eax, dword ptr [ebp-08] <===EAX=78787878
:00575C7D 8D55FC lea edx, dword ptr [ebp-04]
:00575C80 E84F35E9FF call 004091D4
:00575C85 8B45FC mov eax, dword ptr [ebp-04] <===EAX=78787878
:00575C88 8B15845E5900 mov edx, dword ptr [00595E84]
:00575C8E 8B12 mov edx, dword ptr [edx] <===EDX=3702619562
:00575C90 E847EFE8FF call 00404BDC
:00575C95 7436 je 00575CCD <===关键跳转，了也就是说，上面的EAX和EDX必须相等了
:00575C97 6A00 push 00000000
* Possible StringData Ref from Code Obj ->"error"
|
:00575C99 B9C05D5700 mov ecx, 00575DC0
* Possible StringData Ref from Code Obj ->"注册码错误，请与作者联系."
|
:00575C9E BAC85D5700 mov edx, 00575DC8
:00575CA3 A1185D5900 mov eax, dword ptr [00595D18]
:00575CA8 8B00 mov eax, dword ptr [eax]
:00575CAA E83942EFFF call 00469EE8
:00575CAF 8B8300030000 mov eax, dword ptr [ebx+00000300]
:00575CB5 E8E217ECFF call 0043749C
:00575CBA 8B8300030000 mov eax, dword ptr [ebx+00000300]
:00575CC0 8B10 mov edx, dword ptr [eax]
:00575CC2 FF92C0000000 call dword ptr [edx+000000C0]
:00575CC8 E9B5000000 jmp 00575D82
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00575C95(C) <===跳到这里就说明注册成功了，向上看
|
:00575CCD 8B830C030000 mov eax, dword ptr [ebx+0000030C]
:00575CD3 E8F443F4FF call 004BA0CC
:00575CD8 8B830C030000 mov eax, dword ptr [ebx+0000030C]
.......
.......(此处删除一段与算法无关的代码)
* Possible StringData Ref from Code Obj ->"information"
|
:00575D65 B9345E5700 mov ecx, 00575E34
* Possible StringData Ref from Code Obj ->"恭喜您已经注册成功，请重新运行本软件！"
|
:00575D6A BA405E5700 mov edx, 00575E40
:00575D6F A1185D5900 mov eax, dword ptr [00595D18]
:00575D74 8B00 mov eax, dword ptr [eax]
:00575D76 E86D41EFFF call 00469EE8
:00575D7B 8BC3 mov eax, ebx
:00575D7D E89A08EFFF call 0046661C
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00575CC8(U)
|
:00575D82 33C0 xor eax, eax
:00575D84 5A pop edx
:00575D85 59 pop ecx
:00575D86 59 pop ecx
.......
.......
4、很快就你就会发现，关键算法段不在这里。怎么办？再用串式数据参考找啊找，又发现"您已经注册成为了正版用户"，这其实就是当你点击菜单里的注册项时，程序就会判断，如果你已经注册就会显示这个，如果你没有注册就会出现要注册的提示框。呵呵，注册算法部分找到了:-)
依然是用OLLYDBG1.09进行动态调试，设断点005761B5，当你点击菜单里的注册项时，立即断下来。
------------------------********************-----------------------------
:005761B4 56 push esi
* Reference To: kernel32.GetComputerNameA, Ord:0000h
|
:005761B5 E8C60FE9FF Call 00407180 <===获取计算名称函数
:005761BA 83F801 cmp eax, 00000001
:005761BD 1BC0 sbb eax, eax
:005761BF 40 inc eax
:005761C0 84C0 test al, al
:005761C2 750C jne 005761D0 <===如果获取到就从这里跳走了
:005761C4 8BC6 mov eax, esi
:005761C6 E875C6E8FF call 00402840
:005761CB E929010000 jmp 005762F9
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:005761C2(C)
|
:005761D0 8D45F8 lea eax, dword ptr [ebp-08]
:005761D3 8BD6 mov edx, esi <===EDX=POWERLAOS
:005761D5 E8F6E7E8FF call 004049D0
:005761DA 8B55F8 mov edx, dword ptr [ebp-08] <===EDX=POWERLAOS
:005761DD B888805900 mov eax, 00598088
* Possible StringData Ref from Code Obj ->"zjhloveling"
|
:005761E2 B93C635700 mov ecx, 0057633C <===作者内定的字符
:005761E7 E8F8E8E8FF call 00404AE4 <===将计算名和内定的字符串连起来
:005761EC 8D55F4 lea edx, dword ptr [ebp-0C]
:005761EF A188805900 mov eax, dword ptr [00598088] <===EAX="POWERLAOSzjhloveling"
:005761F4 E8DBFEFFFF call 005760D4 <===这就是算法软件机器码的CALL
:005761F9 8B55F4 mov edx, dword ptr [ebp-0C] <===EDX="981727556"这就是我的机器码了
:005761FC B888805900 mov eax, 00598088
:00576201 E82EE6E8FF call 00404834
:00576206 8BC6 mov eax, esi
:00576208 E833C6E8FF call 00402840
:0057620D 8D55F0 lea edx, dword ptr [ebp-10]
:00576210 A188805900 mov eax, dword ptr [00598088]
:00576215 E8BAFEFFFF call 005760D4 <===关键的算法CALL，F8跟进(晕，和生成机器码的CALL是一样的)
:0057621A 8B55F0 mov edx, dword ptr [ebp-10] <===EDX="3702619562"就是注册码了
:0057621D B88C805900 mov eax, 0059808C
:00576222 E80DE6E8FF call 00404834
:00576227 8B83F0020000 mov eax, dword ptr [ebx+000002F0]
.......
.......(省去一段与算法无关的代码)
:005762AA 8D45B0 lea eax, dword ptr [ebp-50]
* Possible StringData Ref from Code Obj ->"zjhloveling"
|
:005762AD BA3C635700 mov edx, 0057633C
:005762B2 E8B1F5E8FF call 00405868
:005762B7 8D55B0 lea edx, dword ptr [ebp-50]
:005762BA 58 pop eax
:005762BB E8F8F5E8FF call 004058B8
:005762C0 7521 jne 005762E3 <===这里是一个关键跳转，如果跳走就要出现注册对话框，如果不跳就显示已经注册
:005762C2 6A00 push 00000000
* Possible StringData Ref from Code Obj ->"提示"
|
:005762C4 B984635700 mov ecx, 00576384
* Possible StringData Ref from Code Obj ->"您已经注册成为了正版用户"
|
:005762C9 BA8C635700 mov edx, 0057638C
:005762CE A1185D5900 mov eax, dword ptr [00595D18]
:005762D3 8B00 mov eax, dword ptr [eax]
:005762D5 E80E3CEFFF call 00469EE8
:005762DA 8BC3 mov eax, ebx
:005762DC E83B03EFFF call 0046661C
:005762E1 EB16 jmp 005762F9
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:00576291(C), :005762C0(C)
|
:005762E3 A1745E5900 mov eax, dword ptr [00595E74]
.......
.......
----------:00576215 call 005760D4 算法CALL，F8跟进)------------------------
.......
.......(省去一段与算法无关的代码)
:0057610A 8B45F4 mov eax, dword ptr [ebp-0C] <===EAX="981727556"
:0057610D E886E9E8FF call 00404A98 <===算出机器码的长度
:00576112 8BC8 mov ecx, eax
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:005760A5(C)
|
:00576114 85C9 test ecx, ecx
:00576116 762A jbe 00576142 <===如果机器码的长度为0，就跳走。这里不跳
:00576118 BE01000000 mov esi, 00000001
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00576140(C) ************最关键的循环结构************
|
:0057611D 8B45FC mov eax, dword ptr [ebp-04] <===EAX="981727556"
:00576120 0FB64430FF movzx eax, byte ptr [eax+esi-01] <===依次取"981727556"字符的ASC值
:00576125 03D8 add ebx, eax
:00576127 69C3D8600B00 imul eax, ebx, 000B60D8
:0057612D BB7B000000 mov ebx, 0000007B
:00576132 33D2 xor edx, edx <===EDX清0
:00576134 F7F3 div ebx <===除以7B
:00576136 69C039300000 imul eax, 00003039 <===得到的商再乘以0x3039
:0057613C 8BD8 mov ebx, eax <===最后的EBX就是我们要的结果
:0057613E 46 inc esi
:0057613F 49 dec ecx
:00576140 75DB jne 0057611D <===向上跳构成一个循环结构
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00576116(C)
|
:00576142 8BC3 mov eax, ebx <===最后EBX就是我们要的注册码了，但还只是16进制的形式DCB17DAA
:00576144 33D2 xor edx, edx
:00576146 52 push edx
:00576147 50 push eax
:00576148 8B45F8 mov eax, dword ptr [ebp-08]
:0057614B E8D033E9FF call 00409520
:00576150 33C0 xor eax, eax
:00576152 5A pop edx
:00576153 59 pop ecx
:00576154 59 pop ecx
:00576155 648910 mov dword ptr fs:[eax], edx
:00576158 6875615700 push 00576175
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00576173(U)
|
:0057615D 8D45F4 lea eax, dword ptr [ebp-0C]
:00576160 E87BE6E8FF call 004047E0
:00576165 8D45FC lea eax, dword ptr [ebp-04]
:00576168 E873E6E8FF call 004047E0
:0057616D C3 ret
......
......
----------------------------------------------------------------------------
5、注册机源程序
=====================VB6.0源程序，在WIN98下测试通过=================
Private Sub Text1_Change()
astr1 = Text1.Text
charlen = Len(astr1)
e = 1
For i = 1 To charlen
sumtmp = Asc(Mid(astr1, i, 1))
If sumtmp < 48 Or sumtmp > 57 Then
e = 2
End If
Next
If charlen = 0 Then e = 3
If e = 1 Then
ebx = "0"
For i = 1 To charlen
sumtmp = bigadd(ebx, CStr(Asc(Mid(astr1, i, 1))))
strtmp = oct2hex(bigmul(sumtmp, "745688"))
strtmp = hex2oct(Right(strtmp, 8))
strtmp = bigdiv(strtmp, "123")
ebx = hex2oct(Right(oct2hex(bigmul(strtmp, "12345")), 8))
Next
laststr = CStr(ebx)
Else
laststr = "你输入的机器码有误"
End If
Text2.Text = laststr
End Sub
'*************上面部分就是真正的实现部分******下面只是大数运算的函数而已********
Function hex2oct(sum16)
'专门将大的16进制转为10进制的函数(目前只支持56位转换)
'函数定义是sum16为56位以下的16进制数的字符串表示形式
astr1 = UCase(sum16)
nlen = Len(astr1)
For i = 1 To nlen '检查16进制的合法性
SUMSUM = Asc(Mid(astr1, i, 1))
If (SUMSUM >= 48 And SUMSUM <= 57) Or (SUMSUM >= 65 And SUMSUM <= 70) Then
e = 1
Else
e = 2
End If
Next i
If nlen = 0 Then
e = 3
End If
Select Case e
Case 1
'在这里填入16进制转为10进制的代码段
bigsum = "0"
For i = 1 To nlen
sesum = CStr(CInt("&h" + Mid(astr1, nlen - i + 1, 1)))
For J = 1 To i - 1
sesum = bigmul(sesum, "16")
Next J
bigsum = bigadd(bigsum, sesum)
Next i
laststr = bigsum
hex2oct = laststr
Case 2
hex2oct = "你的输入非法!"
Case 3
If Option1.value = True Then
hex2oct = "16 进制实时显示"
Else
hex2oct = "10 进制实时显示"
End If
End Select
End Function
Function oct2hex(sum10)
'专门将大的10进制转为16进制的函数(目前只支持56位转换)
'函数定义是sum10为56位以下的10进制数的字符串表示形式
astr1 = sum10
e = 1 '输入操作数正确标志
For i = 1 To Len(astr1) '检查10进制的合法性
SUMSUM = Asc(Mid(astr1, i, 1))
If SUMSUM < 48 Or SUMSUM > 57 Then
e = 2
End If
Next i
If Len(astr1) = 0 Then
e = 3
End If
Select Case e
Case 1
x = Array("", "", "", "", "", "", "", "", "", "", "", "", "", "") '对数组进行定义,每个单元代表4位数，这个数组可以代表56位长度的10进制数
'*******************************************************
Do
nlen = Len(astr1) '得出10进制的长度
p = Int((nlen - 1) / 4) '得出数字占数组的个数(减去1代表数组单元的下标)，每4位数占一个数组单元
i = 0
k = 1
Do
alen = Len(astr1)
If alen <= 4 Then
k = 2
x(i) = astr1
Else
x(i) = Right(astr1, 4) '每次从低位取4位
astr1 = Mid(astr1, 1, alen - 4)
End If
i = i + 1
Loop While k = 1 '完成数据向数组的装入，每个单元为字符串，是从低位向高位的顺序
strnext = ""
strtmp = ""
modtmp = ""
r = 1 '前导去0标志
'***************************************************
For z = p To 0 Step -1 '从最后一位，也是10进制数的最高位开始
modtmp1 = CStr(CLng(modtmp + x(z)) Mod 16) '模作为与下一个数组单元相接合，再求模，直到这后的模
strtmp = CStr(Int(CLng(modtmp + x(z)) / 16))
If Len(strtmp) < 4 And r <> 1 Then '补0也是为了下次大循环的运算,如果是第一个值就不用被0了
For i = 1 To 4 - Len(strtmp)
strtmp = "0" + strtmp
Next i
End If
strnext = strnext + strtmp '得到除以16的商，准备用下一次大循环的运算初始值
modtmp = modtmp1
r = 2
Next z
'***************************************************
lastmod = Hex(Int(modtmp)) + lastmod '其实这就是16进制数了，不用再反向了
astr1 = strnext
i = 1
Do '前导去0循环
nlen = Len(astr1)
If Left(astr1, 1) = "0" Then
astr1 = Right(astr1, nlen - 1)
Else
Exit Do
End If
i = i + 1
Loop While i <= Len(astr1)
If Len(astr1) <= 2 Then '因为前已经加成4个0了，对循环退出的判断
If Len(astr1) = 0 Then '防止到下面来个CInt(astr1)类型不符
Exit Do
End If
If CInt(astr1) < 16 Then
Exit Do
End If
End If
Loop
'*****************************************************
If Len(astr1) = 0 Then
laststr = lastmod
Else
laststr = Hex(CInt(astr1)) + lastmod
End If
oct2hex = laststr
Case 2
oct2hex = "你的输入非法!"
Case 3
If Option1.value = True Then
oct2hex = "16 进制实时显示"
Else
oct2hex = "10 进制实时显示"
End If
End Select
End Function
Function bigadd(add1, add2)
'大数相加函数，参数定义add1,add2均为10进制数的字符串表示形式，限定为28位长度。
'返回值也是10进制的字符串形式。当然还有一个错误返回值是"inputerror"
'每一个0代表4位数，第一个0代表1-4位，第2个0代表5-8位，第3个0代表9-12们，类推，第7个0代表25-28位(这是从最低位开始数哟)
astr1 = add1
astr2 = add2
e = 1 '输入操作数正确标志
For i = 1 To Len(astr1) '检查第一输入的合法性
SUMSUM = Asc(Mid(astr1, i, 1))
If SUMSUM < 48 Or SUMSUM > 57 Then
e = 2
End If
Next i
For i = 1 To Len(astr2) '检查第二个输入的合法性
SUMSUM = Asc(Mid(astr2, i, 1))
If SUMSUM < 48 Or SUMSUM > 57 Then
e = 2
End If
Next i
If Len(astr1) = 0 Or Len(astr2) = 0 Then '其中任意一个操作数不能为空
e = 2
End If
If e = 1 Then
A = Array(0, 0, 0, 0, 0, 0, 0)
i = 0
k = 1
Do
alen = Len(astr1)
If alen <= 4 Then
k = 2
A(i) = CLng(astr1)
Else
A(i) = CLng(Right(astr1, 4)) '每次从低位取4位
astr1 = Mid(astr1, 1, alen - 4)
End If
i = i + 1
Loop While k = 1
'到这里完成将10进制数第4位放入数组a
wa = i '这里代表a数组里有几个数
B = Array(0, 0, 0, 0, 0, 0, 0)
i = 0
k = 1
Do
alen = Len(astr2)
If alen <= 4 Then
k = 2
B(i) = CLng(astr2)
Else
B(i) = CLng(Right(astr2, 4)) '每次取4位
astr2 = Mid(astr2, 1, alen - 4)
End If
i = i + 1
Loop While k = 1
'到这里完成将10进制数第4位放入数组b
wb = i '这里代表b数组里有几个数
C = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) '定义最终结果数组，每一个0代表4位数
'---------------------------------相加代码段--------------------------------
If wa > wb Then
w = wa - 1
Else
w = wb - 1
End If
i = 0
tmp2 = 0
Do While i <= w '以数组最多的数决定循环次数
tmp = A(i) + B(i) + tmp2
C(i) = (tmp Mod 10000) '只留4位
tmp2 = Int(tmp / 10000) '商自动进入下一位
i = i + 1
If i = 7 Then
Exit Do
End If
Loop
C(i) = tmp2 '最后一个进位值
k = 1
For i = 13 To 0 Step -1
If C(i) <> 0 Or k <> 1 Then
ttmp = CStr(C(i))
If Len(ttmp) < 4 And k <> 1 Then '当出现某个数组中的数为0890的情况，如果不补0，就会出错了。当然也要考第一个数防止出现数字最前面出现多余的0的情况
For J = 1 To 4 - Len(ttmp)
ttmp = "0" + ttmp
Next
End If
laststr3 = laststr3 + ttmp
k = 2
End If
Next i
If k = 1 Then '两个0两相加，就可以一次都不经过
bigadd = "0"
Else
bigadd = laststr3
End If
Else
bigadd = "inputerror" '说明输入错误了
End If
'---------------------------------相加代码段结束--------------------------------
End Function
Function bigmul(mul1, mul2)
'大数相乘函数，参数定义mul1,mul2均为10进制数的字符串表示形式，限定为28位长度。
'返回值也是10进制的字符串形式。当然还有一个错误返回值是"inputerror"
'每一个0代表4位数，第一个0代表1-4位，第2个0代表5-8位，第3个0代表9-12们，类推，第7个0代表25-28位(这是从最低位开始数哟)
astr1 = mul1
astr2 = mul2
e = 1 '输入操作数正确标志
For i = 1 To Len(astr1) '检查第一输入的合法性
SUMSUM = Asc(Mid(astr1, i, 1))
If SUMSUM < 48 Or SUMSUM > 57 Then
e = 2
End If
Next i
For i = 1 To Len(astr2) '检查第二个输入的合法性
SUMSUM = Asc(Mid(astr2, i, 1))
If SUMSUM < 48 Or SUMSUM > 57 Then
e = 2
End If
Next i
If Len(astr1) = 0 Or Len(astr2) = 0 Then '其中任意一个操作数不能为空
e = 2
End If
If e = 1 Then
A = Array(0, 0, 0, 0, 0, 0, 0)
i = 0
k = 1
Do
alen = Len(astr1)
If alen <= 4 Then
k = 2
A(i) = CLng(astr1)
Else
A(i) = CLng(Right(astr1, 4)) '每次从低位取4位
astr1 = Mid(astr1, 1, alen - 4)
End If
i = i + 1
Loop While k = 1
'到这里完成将10进制数第4位放入数组a
wa = i '这里代表a数组里有几个数
B = Array(0, 0, 0, 0, 0, 0, 0)
i = 0
k = 1
Do
alen = Len(astr2)
If alen <= 4 Then
k = 2
B(i) = CLng(astr2)
Else
B(i) = CLng(Right(astr2, 4)) '每次取4位
astr2 = Mid(astr2, 1, alen - 4)
End If
i = i + 1
Loop While k = 1
'到这里完成将10进制数第4位放入数组b
wb = i '这里代表b数组里有几个数
C = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) '定义最终结果数组，每一个0代表4位数
'---------------------------------相乘代码段开始(不考虑负数情况)--------------------------------
For i = 0 To 13
C(i) = 0
Next i
For i = 0 To 6
tmp2 = 0
For J = 0 To 6
sumtmp = A(J) * B(i) + tmp2 + C(i + J)
C(i + J) = (sumtmp Mod 10000)
tmp2 = Int(sumtmp / 10000)
Next J
C(i + J) = tmp2
Next i
k = 1
For i = 13 To 0 Step -1
If C(i) <> 0 Or k <> 1 Then
ttmp = CStr(C(i))
If Len(ttmp) < 4 And k <> 1 Then '当出现某个数组中的数为0890的情况，如果不补0，就会出错了。当然也要考第一个数防止出现数字最前面出现多余的0的情况
For J = 1 To 4 - Len(ttmp)
ttmp = "0" + ttmp
Next
End If
laststr4 = laststr4 + ttmp
k = 2
End If
Next i
If k = 1 Then 'k=1 说明一次都没经过，结果就为0
bigmul = "0"
Else
bigmul = laststr4
End If
Else
bigmul = "inputerror"
End If
End Function
Function bigdiv(mul1, mul2)
'大数相除函数，参数定义mul1,mul2均为10进制数的字符串表示形式
'这里的被除数只能在long的范围内
astr1 = mul1
nlen = Len(astr1)
astr2 = mul2
lasturn = ""
laststr = "" '最后的商
k = 1
For i = 1 To nlen
strtmp = lasturn + Mid(astr1, i, 1)
sumtmp = CLng(strtmp)
If sumtmp < CLng(astr2) Then
lasturn = CStr(strtmp)
If k = 2 Then laststr = laststr & "0"
Else
laststr = laststr & CStr(Int(sumtmp / CLng(astr2)))
lasturn = CStr(sumtmp Mod CLng(astr2))
k = 2
End If
Next
bigdiv = laststr
'lasturn就是模了
End Function
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